If 3 is a root of x^2 + kx - 24 = 0,it is als | vedclass

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(C) Given that $3$ is a root of the equation $x^2 + kx - 24 = 0$.Substituting $x = 3$ into the equation:$(3)^2 + k(3) - 24 = 0$$9 + 3k - 24 = 0$$3k -

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$x^2 - kx + 6 = 0$

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(C) Given that $3$ is a root of the equation $x^2 + kx - 24 = 0$.Substituting $x = 3$ into the equation:$(3)^2 + k(3) - 24 = 0$$9 + 3k - 24 = 0$$3k - 15 = 0$$3k = 15$$k = 5$Now,check which option satisfies the condition that $x = 3$ is a root when $k = 5$:For option $(C)$,$x^2 - kx + 6 = 0$ becomes $x^2 - 5x + 6 = 0$.Substituting $x = 3$: $(3)^2 - 5(3) + 6 = 9 - 15 + 6 = 0$.Thus,$3$ is a root of $x^2 - kx + 6 = 0$.

If $3$ is a root of $x^2 + kx - 24 = 0$,it is also a root of

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