If y = frac{x^{2/3} - x^{-1/3}}{x^{2/3} + x^{ | vedclass

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(A) Given $y = \frac{x^{2/3} - x^{-1/3}}{x^{2/3} + x^{-1/3}}$.Multiply numerator and denominator by $x^{1/3}$:$y = \frac{x^{2/3} \cdot x^{1/3} - x^{-1

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$2$

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(A) Given $y = \frac{x^{2/3} - x^{-1/3}}{x^{2/3} + x^{-1/3}}$.Multiply numerator and denominator by $x^{1/3}$:$y = \frac{x^{2/3} \cdot x^{1/3} - x^{-1/3} \cdot x^{1/3}}{x^{2/3} \cdot x^{1/3} + x^{-1/3} \cdot x^{1/3}} = \frac{x - 1}{x + 1}$.Now,differentiate with respect to $x$ using the quotient rule:$y_1 = \frac{d}{dx} \left( \frac{x-1}{x+1} \right) = \frac{(x+1)(1) - (x-1)(1)}{(x+1)^2}$.$y_1 = \frac{x + 1 - x + 1}{(x+1)^2} = \frac{2}{(x+1)^2}$.Therefore,$(x+1)^2 y_1 = 2$.

If $y = \frac{x^{2/3} - x^{-1/3}}{x^{2/3} + x^{-1/3}}$,$x \neq 0$,then $(x+1)^2 y_1 = $

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