If y = A cos nx + B sin nx,then frac{d^2 y}{d | vedclass

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(A) Given $y = A \cos nx + B \sin nx$  ...$(i)$ Differentiating with respect to $x$,we get: $\frac{dy}{dx} = -An \sin nx + Bn \cos nx$ Again different

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$-n^2 y$

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(A) Given $y = A \cos nx + B \sin nx$  ...$(i)$ Differentiating with respect to $x$,we get: $\frac{dy}{dx} = -An \sin nx + Bn \cos nx$ Again differentiating with respect to $x$,we get: $\frac{d^2 y}{dx^2} = -An^2 \cos nx - Bn^2 \sin nx$ Factoring out $-n^2$: $\frac{d^2 y}{dx^2} = -n^2 (A \cos nx + B \sin nx)$ Substituting $y$ from equation $(i)$: $\frac{d^2 y}{dx^2} = -n^2 y$

If $y = A \cos nx + B \sin nx$,then $\frac{d^2 y}{dx^2} = $

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