If $\triangle ABC$ is right-angled at $A$,where $A \equiv (4, 2, x)$,$B \equiv (3, 1, 8)$,and $C \equiv (2, -1, 2)$,then the value of $x$ is

  • A
    $4$
  • B
    $2$
  • C
    $3$
  • D
    $1$

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