If tan 3 theta = cot theta,then theta = | vedclass

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Question

(A) Given the equation $	an 3	heta = \cot 	heta$. We know that $\cot 	heta = 	an(\frac{\pi}{2} - 	heta)$. So,$	an 3	heta = 	an(\frac{\pi}{2}

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$\frac{(2n+1)\pi}{8}, n \in Z$

Vedclass · Answer

(A) Given the equation $	an 3	heta = \cot 	heta$. We know that $\cot 	heta = 	an(\frac{\pi}{2} - 	heta)$. So,$	an 3	heta = 	an(\frac{\pi}{2} - 	heta)$. The general solution for $	an x = 	an y$ is $x = n\pi + y$,where $n \in Z$. Therefore,$3	heta = n\pi + (\frac{\pi}{2} - 	heta)$. Adding $	heta$ to both sides,we get $4	heta = n\pi + \frac{\pi}{2}$. $4	heta = \frac{(2n+1)\pi}{2}$. Dividing by $4$,we get $	heta = \frac{(2n+1)\pi}{8}$,where $n \in Z$.

If $\tan 3 \theta = \cot \theta$,then $\theta = $

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