If begin{bmatrix} x & 0 1 & y end{bmatrix} + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the matrix equation: $\begin{bmatrix} x & 0 \ 1 & y \end{bmatrix} + \begin{bmatrix} -2 & 1 \ 3 & 4 \end{bmatrix} = \begin{bmatrix} 3 & 5 \

Vedclass · Accepted Answer

$x = 3, y = -2$

Vedclass · Answer

(B) Given the matrix equation: $\begin{bmatrix} x & 0 \ 1 & y \end{bmatrix} + \begin{bmatrix} -2 & 1 \ 3 & 4 \end{bmatrix} = \begin{bmatrix} 3 & 5 \ 6 & 3 \end{bmatrix} - \begin{bmatrix} 2 & 4 \ 2 & 1 \end{bmatrix}$ First,perform the addition on the left side: $\begin{bmatrix} x - 2 & 0 + 1 \ 1 + 3 & y + 4 \end{bmatrix} = \begin{bmatrix} x - 2 & 1 \ 4 & y + 4 \end{bmatrix}$ Next,perform the subtraction on the right side: $\begin{bmatrix} 3 - 2 & 5 - 4 \ 6 - 2 & 3 - 1 \end{bmatrix} = \begin{bmatrix} 1 & 1 \ 4 & 2 \end{bmatrix}$ Equating the corresponding elements of the two matrices: $x - 2 = 1 \Rightarrow x = 3$ $y + 4 = 2 \Rightarrow y = -2$ Thus,the values are $x = 3$ and $y = -2$.

If $\begin{bmatrix} x & 0 \\ 1 & y \end{bmatrix} + \begin{bmatrix} -2 & 1 \\ 3 & 4 \end{bmatrix} = \begin{bmatrix} 3 & 5 \\ 6 & 3 \end{bmatrix} - \begin{bmatrix} 2 & 4 \\ 2 & 1 \end{bmatrix}$,then find the values of $x$ and $y$.

Similar Questions

If $A = \begin{bmatrix} \lambda & 1 \\ -1 & -\lambda \end{bmatrix}$,then for what value of $\lambda$ is $A^2 = O$?

If $A + B = \begin{bmatrix} 1 & 0 \\ 1 & 1 \end{bmatrix}$ and $A - 2B = \begin{bmatrix} -1 & 1 \\ 0 & -1 \end{bmatrix}$,then $A=$

Simplify $\cos \theta \begin{bmatrix} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \end{bmatrix} + \sin \theta \begin{bmatrix} \sin \theta & -\cos \theta \\ \cos \theta & \sin \theta \end{bmatrix}$.

Let $A = \begin{bmatrix} 1 & -1 & 0 \\ 0 & 1 & -1 \\ 0 & 0 & 1 \end{bmatrix}$ and $B = 7A^{20} - 20A^{7} + 2I$,where $I$ is an identity matrix of order $3 \times 3$. If $B = [b_{ij}]$,then $b_{13}$ is equal to $....$

If $A = \begin{bmatrix} 1 & 1 \\ 1 & 1 \end{bmatrix}$,then $A^{100} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module