If A = begin{bmatrix} 4 & 2 3 & 4 end{bmatri | vedclass

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(B) Given $A = \begin{bmatrix} 4 & 2 \ 3 & 4 \end{bmatrix}$.The adjoint of a $2 	imes 2$ matrix $\begin{bmatrix} a & b \ c & d \end{bmatrix}$ is gi

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$10$

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(B) Given $A = \begin{bmatrix} 4 & 2 \ 3 & 4 \end{bmatrix}$.The adjoint of a $2 	imes 2$ matrix $\begin{bmatrix} a & b \ c & d \end{bmatrix}$ is given by $\begin{bmatrix} d & -b \ -c & a \end{bmatrix}$.Therefore,$adj\,A = \begin{bmatrix} 4 & -2 \ -3 & 4 \end{bmatrix}$.Now,calculate the determinant $|adj\,A|$:$|adj\,A| = (4 	imes 4) - (-3 	imes -2)$$|adj\,A| = 16 - 6$$|adj\,A| = 10$.Alternatively,using the property $|adj\,A| = |A|^{n-1}$ where $n$ is the order of the matrix:$|A| = (4 	imes 4) - (3 	imes 2) = 16 - 6 = 10$.Since $n=2$,$|adj\,A| = |A|^{2-1} = |A|^1 = 10$.

If $A = \begin{bmatrix} 4 & 2 \\ 3 & 4 \end{bmatrix}$,then $|adj\,A|$ is equal to

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