If $\vec{a} = \hat{i} + 2\hat{j} + 2\hat{k}$,$|\vec{b}| = 5$,and the angle between $\vec{a}$ and $\vec{b}$ is $\frac{\pi}{6}$,then the area of the triangle formed by these two vectors as two sides is

  • A
    $\frac{15}{2}$
  • B
    $15$
  • C
    $\frac{15}{4}$
  • D
    $\frac{15\sqrt{3}}{2}$

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