If tan 2theta tan theta = 1,then the general | vedclass

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(A) Given the equation: $	an 2	heta 	an 	heta = 1$This can be rewritten as: $	an 2	heta = \frac{1}{	an 	heta} = \cot 	heta$Using the identity

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$\left( n + \frac{1}{2} \right) \frac{\pi}{3}$

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(A) Given the equation: $	an 2	heta 	an 	heta = 1$This can be rewritten as: $	an 2	heta = \frac{1}{	an 	heta} = \cot 	heta$Using the identity $\cot 	heta = 	an \left( \frac{\pi}{2} - 	heta ight)$,we get:$	an 2	heta = 	an \left( \frac{\pi}{2} - 	heta ight)$The general solution for $	an x = 	an \alpha$ is $x = n\pi + \alpha$,where $n \in \mathbb{Z}$.Therefore: $2	heta = n\pi + \left( \frac{\pi}{2} - 	heta ight)$Adding $	heta$ to both sides: $3	heta = n\pi + \frac{\pi}{2}$Dividing by $3$: $	heta = \frac{n\pi}{3} + \frac{\pi}{6} = \left( n + \frac{1}{2} ight) \frac{\pi}{3}$.

If $\tan 2\theta \tan \theta = 1$,then the general value of $\theta$ is

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