If f: R rightarrow R is defined by f(x) = fra | vedclass

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Question

(B) Given that $f(x) = \frac{x}{x^{2}+1}$.
First,calculate $f(2)$ by substituting $x = 2$ into the function:
$f(2) = \frac{2}{2^{2}+1} = \frac{2}{4+

Vedclass · Accepted Answer

$\frac{10}{29}$

Vedclass · Answer

(B) Given that $f(x) = \frac{x}{x^{2}+1}$.
First,calculate $f(2)$ by substituting $x = 2$ into the function:
$f(2) = \frac{2}{2^{2}+1} = \frac{2}{4+1} = \frac{2}{5}$.
Now,calculate $f(f(2))$ by substituting $f(2) = \frac{2}{5}$ back into the function:
$f(f(2)) = f\left(\frac{2}{5}ight) = \frac{\frac{2}{5}}{\left(\frac{2}{5}ight)^{2}+1}$.
Simplify the denominator:
$\left(\frac{2}{5}ight)^{2} + 1 = \frac{4}{25} + 1 = \frac{4+25}{25} = \frac{29}{25}$.
Therefore,$f(f(2)) = \frac{\frac{2}{5}}{\frac{29}{25}} = \frac{2}{5} 	imes \frac{25}{29} = \frac{2 	imes 5}{29} = \frac{10}{29}$.

If $f: R \rightarrow R$ is defined by $f(x) = \frac{x}{x^{2}+1}$,find $f(f(2))$.

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