If $R$ is the radius of orbit of a satellite,then the kinetic energy of the satellite is

$A$ satellite is revolving around a planet of mass $M$ in an elliptical orbit of semi-major axis $a$. What is the speed of the satellite when it is at a distance $a/2$ from the planet?

An artificial satellite moving in a circular orbit around the earth has a total (kinetic + potential) energy $E_0$. Its potential energy is

$A$ satellite is orbiting the Earth with an orbital velocity $v_0$. If it is suddenly stopped and allowed to fall onto the Earth,what will be its velocity when it hits the Earth's surface? (Let $v_e$ be the escape velocity from the Earth's surface.)

$A$ satellite of mass $m$ rotates around the Earth in a circular orbit of radius $R$. If the angular momentum of the satellite is $J$, then its kinetic energy $(K)$ and the total energy $(E)$ of the satellite are:

When a satellite going round the Earth in a circular orbit of radius $r$ and speed $v$ loses some of its energy,then $r$ and $v$ change as: