જો 1-cot 23^{circ}=frac{x}{1-cot 22^{circ}} હ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) આપેલ છે,$1-\cot 23^{\circ}=\frac{x}{1-\cot 22^{\circ}}$$x = (1-\cot 23^{\circ})(1-\cot 22^{\circ})$$x = (1 - \frac{\cos 23^{\circ}}{\sin 23^{\circ

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) આપેલ છે,$1-\cot 23^{\circ}=\frac{x}{1-\cot 22^{\circ}}$$x = (1-\cot 23^{\circ})(1-\cot 22^{\circ})$$x = (1 - \frac{\cos 23^{\circ}}{\sin 23^{\circ}})(1 - \frac{\cos 22^{\circ}}{\sin 22^{\circ}})$$x = \frac{(\sin 23^{\circ} - \cos 23^{\circ})(\sin 22^{\circ} - \cos 22^{\circ})}{\sin 23^{\circ} \sin 22^{\circ}}$$x = \frac{\sin 23^{\circ} \sin 22^{\circ} - \sin 23^{\circ} \cos 22^{\circ} - \cos 23^{\circ} \sin 22^{\circ} + \cos 23^{\circ} \cos 22^{\circ}}{\sin 23^{\circ} \sin 22^{\circ}}$$\cos(A-B) = \cos A \cos B + \sin A \sin B$ અને $\sin(A+B) = \sin A \cos B + \cos A \sin B$ નો ઉપયોગ કરતા:$x = \frac{\cos(23^{\circ}-22^{\circ}) - \sin(23^{\circ}+22^{\circ})}{\sin 23^{\circ} \sin 22^{\circ}}$$x = \frac{\cos 1^{\circ} - \sin 45^{\circ}}{\sin 23^{\circ} \sin 22^{\circ}}$$2 \sin A \sin B = \cos(A-B) - \cos(A+B)$ નો ઉપયોગ કરતા:$x = \frac{2(\cos 1^{\circ} - \sin 45^{\circ})}{\cos(23^{\circ}-22^{\circ}) - \cos(23^{\circ}+22^{\circ})}$$x = \frac{2(\cos 1^{\circ} - \frac{1}{\sqrt{2}})}{\cos 1^{\circ} - \cos 45^{\circ}} = \frac{2(\cos 1^{\circ} - \frac{1}{\sqrt{2}})}{\cos 1^{\circ} - \frac{1}{\sqrt{2}}} = 2$

જો $1-\cot 23^{\circ}=\frac{x}{1-\cot 22^{\circ}}$ હોય,તો $x=$

Similar Questions

જો $\frac{\sin (A+B)}{\sin (A-B)}=\frac{\cos (C+D)}{\cos (C-D)}$ હોય,તો $\tan A \cot B=$

$\sin 36^\circ \sin 72^\circ \sin 108^\circ \sin 144^\circ = $

જો $\cos \theta = -\frac{\sqrt{3}}{2}$ અને $\sin \alpha = -\frac{3}{5}$ હોય,જ્યાં $\theta$ ત્રીજા ચરણમાં નથી,તો $\frac{2 \tan \alpha + \sqrt{3} \tan \theta}{\cot^2 \theta + \cos \alpha}$ ની કિંમત શોધો.

${\left( \frac{\cos A + \cos B}{\sin A - \sin B} \right)^n} + {\left( \frac{\sin A + \sin B}{\cos A - \cos B} \right)^n}$ ($n$ એ પૂર્ણાંક છે) $=$

Vedclass Test Series

Exam Paper Generator

Online Exam Module