If $A = \{x \in [0, 2\pi] : \tan x - \tan^2 x > 0\}$ and $B = \{x \in [0, 2\pi] : |\sin x| < \frac{1}{2}\}$,then $A \cap B =$

  • A
    $\left(0, \frac{\pi}{6}\right) \cup \left(\pi, \frac{7\pi}{6}\right)$
  • B
    $\left(0, \frac{\pi}{4}\right) \cup \left(\pi, \frac{7\pi}{6}\right)$
  • C
    $\left(0, \frac{\pi}{6}\right) \cup \left(\frac{5\pi}{6}, \frac{7\pi}{6}\right)$
  • D
    $\left(\frac{\pi}{6}, \frac{7\pi}{6}\right)$

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