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(A-III, B-VI, C-II, D-V) Given $f(x) = \begin{cases} x+4 & 	ext{for } x < -4 \ 3x+2 & 	ext{for } -4 \leq x < 4 \ x-4 & 	ext{for } x \geq 4 \end{c

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(A-III, B-VI, C-II, D-V) Given $f(x) = \begin{cases} x+4 & 	ext{for } x $(A)$ $f(-5) + f(-4) = (-5+4) + (3(-4)+2) = -1 + (-12+2) = -1 - 10 = -11$. Thus,$(A)$ matches $(iii)$. $(B)$ $f(|f(-8)|) = f(|-8+4|) = f(|-4|) = f(4) = 4-4 = 0$. Thus,$(B)$ matches $(vi)$. $(C)$ $f(f(-7) + f(3)) = f((-7+4) + (3(3)+2)) = f(-3 + 11) = f(8) = 8-4 = 4$. Thus,$(C)$ matches $(ii)$. $(D)$ $f(f(f(f(0)))) + 1 = f(f(f(3(0)+2))) + 1 = f(f(f(2))) + 1 = f(f(3(2)+2)) + 1 = f(f(8)) + 1 = f(8-4) + 1 = f(4) + 1 = (4-4) + 1 = 1$. Thus,$(D)$ matches $(v)$.

List-$I$	List-$II$
$(A)$ $f(-5) + f(-4)$	$(i)$ $14$
$(B)$ $f(\|f(-8)\|)$	$(ii)$ $4$
$(C)$ $f(f(-7) + f(3))$	$(iii)$ $-11$
$(D)$ $f(f(f(f(0)))) + 1$	$(iv)$ $-1$
	$(v)$ $1$
	$(vi)$ $0$

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