If $u=\sin ^{-1}\left(\frac{x^4+y^4}{x+y}\right)$,then $x \frac{\partial u}{\partial x}+y \frac{\partial u}{\partial y}$ is equal to

  • A
    $3 u$
  • B
    $4 u$
  • C
    $3 \sin u$
  • D
    $3 \tan u$

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