If $1, \omega, \omega^2, \ldots, \omega^8$ are the roots of the equation $x^9-1=0$,then $\sum_{r=1}^8 \left(\omega^r\right)^{99} =$

  • A
    $0$
  • B
    $8$
  • C
    $1$
  • D
    $\omega$

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