જો $A+B+C=\frac{\pi}{3}$ હોય,તો $\sin \left(\frac{\pi-6A}{6}\right)+\sin \left(\frac{\pi-6B}{6}\right)+\sin C=$

  • A
    $-1+4 \cos \left(\frac{\pi-6A}{12}\right) \cos \left(\frac{\pi-6B}{12}\right) \sin \frac{C}{2}$
  • B
    $4 \sin \left(\frac{\pi+6A}{12}\right) \sin \left(\frac{\pi+6B}{12}\right) \cos \frac{C}{2}$
  • C
    $1-4 \cos \left(\frac{\pi-6A}{12}\right) \cos \left(\frac{\pi-6B}{12}\right) \cos \left(\frac{\pi-6C}{12}\right)$
  • D
    $4 \cos \left(\frac{\pi-6A}{12}\right) \cos \left(\frac{\pi-6B}{12}\right) \sin \frac{C}{2}$

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