If $\frac{6 x^4+13 x^3+2 x^2-x+3}{2 x^2+3 x-2}=f(x)+\frac{A}{a x-1}+\frac{B}{x+b}$ then $f(1)+a \cdot B+b \cdot A=$

  • A
    $8$
  • B
    $12$
  • C
    $4$
  • D
    $6$

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