જો $\int \frac{2 x^2}{\left(2 x^2+\alpha\right)\left(x^2+5\right)} d x=\frac{\sqrt{5}}{3} \tan ^{-1} \frac{x}{\sqrt{5}}-\frac{\sqrt{2}}{3} \tan ^{-1} \frac{x}{\sqrt{2}}+c$ હોય, તો $\alpha=$

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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Similar Questions

જો $\int \frac{2x^2+3}{(x^2-1)(x^2-4)} dx = \log \left[\left(\frac{x-2}{x+2}\right)^a \cdot \left(\frac{x+1}{x-1}\right)^b\right] + c$,(જ્યાં $c$ એ સંકલનનો અચળાંક છે),તો $a+b$ ની કિંમત શોધો.

$\int \frac{x^3}{x^4+5 x^2+4} \,d x=$

જો $\int \frac{\sin x}{\sin 4x} dx = \alpha \log \left| \frac{1+\sin x}{1-\sin x} \right| + \beta \log \left| \frac{1+\sqrt{2} \sin x}{1-\sqrt{2} \sin x} \right| + c$ હોય, તો $32(\alpha + \beta^2) = $ ની કિંમત શોધો.

જો $\int \frac{3x+1}{(x-1)^3(x+1)} dx = A \cdot \log \left|\frac{x+1}{x-1}\right| + \frac{B}{x-1} + \frac{C}{(x-1)^2} + D$ હોય,તો $A+B+C=$

$\int \frac{1}{(x - 1)(x^2 + 1)} dx = $

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