If $f(x, y) = \frac{\cos(x - 4y)}{\cos(x + 4y)}$, then $\left. \frac{\partial f}{\partial x} \right|_{y = \frac{x}{4}}$ is equal to:

  • A
    -$1$
  • B
    $0$
  • C
    $1$
  • D
    $2$

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