If O is the origin and OP = 3 with direction | vedclass

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(B) The direction ratios of the line $OP$ are given as $a = -1$,$b = 2$,and $c = -2$.The direction cosines $(l, m, n)$ are calculated by dividing the

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$(-1, 2, -2)$

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(B) The direction ratios of the line $OP$ are given as $a = -1$,$b = 2$,and $c = -2$.The direction cosines $(l, m, n)$ are calculated by dividing the direction ratios by the magnitude $\sqrt{a^2 + b^2 + c^2}$.Magnitude $= \sqrt{(-1)^2 + 2^2 + (-2)^2} = \sqrt{1 + 4 + 4} = \sqrt{9} = 3$.Thus,$l = \frac{-1}{3}$,$m = \frac{2}{3}$,and $n = \frac{-2}{3}$.The coordinates of point $P$ are given by $(lr, mr, nr)$,where $r = OP = 3$.Coordinates of $P = (3 	imes \frac{-1}{3}, 3 	imes \frac{2}{3}, 3 	imes \frac{-2}{3}) = (-1, 2, -2)$.

If $O$ is the origin and $OP = 3$ with direction ratios $-1, 2, -2$,then the coordinates of $P$ are:

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