If f(x) = 2x^6 + 3x^4 + 4x^2,then f'(x) is: | vedclass

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(B) Given $f(x) = 2x^6 + 3x^4 + 4x^2$. First,we check if $f(x)$ is an even or odd function. $f(-x) = 2(-x)^6 + 3(-x)^4 + 4(-x)^2 = 2x^6 + 3x^4 + 4x^2

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An odd function

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(B) Given $f(x) = 2x^6 + 3x^4 + 4x^2$. First,we check if $f(x)$ is an even or odd function. $f(-x) = 2(-x)^6 + 3(-x)^4 + 4(-x)^2 = 2x^6 + 3x^4 + 4x^2 = f(x)$. Since $f(-x) = f(x)$,$f(x)$ is an even function. Now,we find the derivative $f'(x)$: $f'(x) = \frac{d}{dx}(2x^6 + 3x^4 + 4x^2) = 12x^5 + 12x^3 + 8x$. To check if $f'(x)$ is even or odd,we evaluate $f'(-x)$: $f'(-x) = 12(-x)^5 + 12(-x)^3 + 8(-x) = -12x^5 - 12x^3 - 8x = -(12x^5 + 12x^3 + 8x) = -f'(x)$. Since $f'(-x) = -f'(x)$,$f'(x)$ is an odd function.

If $f(x) = 2x^6 + 3x^4 + 4x^2$,then $f'(x)$ is:

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