If $\int e^{3x} \cos 4x \,dx = e^{3x} (A \sin 4x + B \cos 4x) + c$,then:

  • A
    $4A = 3B$
  • B
    $2A = 3B$
  • C
    $3A = 4B$
  • D
    $4B + 3A = 1$

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