If $y = (A + Bx) e^{mx} + (m - 1)^{-2} e^x$,then $\frac{d^2y}{dx^2} - 2m \frac{dy}{dx} + m^2y$ is equal to:

  • A
    $e^x$
  • B
    $e^{mx}$
  • C
    $e^{-mx}$
  • D
    $e^{(1 - m)x}$

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