If $f(x) = \begin{cases} \frac{a + 3\cos x}{x^2}, & x < 0 \\ b\tan \left( \frac{\pi}{[x + 3]} \right), & x \geqslant 0 \end{cases}$ is continuous at $x = 0$,then:

  • A
    $a = 3, b = \frac{-\sqrt{3}}{2}$
  • B
    $a = -3, b = \frac{-\sqrt{3}}{2}$
  • C
    $a = -3, b = \frac{\sqrt{3}}{2}$
  • D
    $a = 3, b = \frac{\sqrt{3}}{2}$

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