If a body is in equilibrium under a set of no | vedclass

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(B) For a body to be in equilibrium,the vector sum of all forces acting on it must be zero,i.e.,$\sum \vec{F} = 0$.If there are only two forces,they m

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$3$

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(B) For a body to be in equilibrium,the vector sum of all forces acting on it must be zero,i.e.,$\sum \vec{F} = 0$.If there are only two forces,they must be equal in magnitude and opposite in direction to cancel each other out,which means they must be collinear.Since the problem states that the forces are non-collinear,two forces cannot satisfy the equilibrium condition.Therefore,at least three non-collinear forces are required to form a closed triangle of vectors,such that their resultant is zero.An example of this is three equal forces acting at angles of $120^{\circ}$ to each other.Thus,the minimum number of forces is $3$.

If a body is in equilibrium under a set of non-collinear forces,then the minimum number of forces has to be

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