If a rubber ball is taken to a depth of 200 | vedclass

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Question

(D) The bulk modulus $K$ is defined as the ratio of the change in pressure $\Delta P$ to the volumetric strain $\Delta V/V$.Given:Depth $h = 200 \ m$D

Vedclass · Accepted Answer

$2 	imes 10^9$

Vedclass · Answer

(D) The bulk modulus $K$ is defined as the ratio of the change in pressure $\Delta P$ to the volumetric strain $\Delta V/V$.Given:Depth $h = 200 \ m$Density of water $ho = 1 	imes 10^3 \ kg/m^3$Acceleration due to gravity $g = 10 \ m/s^2$Volumetric strain $\frac{\Delta V}{V} = 0.1 \% = \frac{0.1}{100} = 10^{-3}$The change in pressure at depth $h$ is given by $\Delta P = h ho g$.$\Delta P = 200 	imes 10^3 	imes 10 = 2 	imes 10^6 \ N/m^2$.Now,calculate the bulk modulus $K$:$K = \frac{\Delta P}{\Delta V/V} = \frac{2 	imes 10^6}{10^{-3}} = 2 	imes 10^9 \ N/m^2$.Therefore,the correct option is $D$.

If a rubber ball is taken to a depth of $200 \ m$ in a pool,its volume decreases by $0.1 \%$. If the density of the water is $1 \times 10^3 \ kg/m^3$ and $g = 10 \ m/s^2$,then the bulk modulus (volume elasticity) in $N/m^2$ will be:

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