If lines $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}$ and $\frac{x-3}{1}=\frac{y-k}{2}=\frac{z-0}{1}$ intersect,then the value of $k$ is

  • A
    $\frac{9}{2}$
  • B
    $\frac{1}{2}$
  • C
    $\frac{5}{2}$
  • D
    $\frac{7}{2}$

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