If one root of the quadratic equation ix^2 - | vedclass

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(A) Given the quadratic equation $ix^2 - 2(i + 1)x + (2 - i) = 0$.Let the roots be $\alpha$ and $\beta$. We are given $\beta = 2 - i$.The product of t

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$-i$

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(A) Given the quadratic equation $ix^2 - 2(i + 1)x + (2 - i) = 0$.Let the roots be $\alpha$ and $\beta$. We are given $\beta = 2 - i$.The product of the roots for a quadratic equation $ax^2 + bx + c = 0$ is given by $\alpha \cdot \beta = \frac{c}{a}$.Here,$a = i$ and $c = 2 - i$.Therefore,$\alpha \cdot (2 - i) = \frac{2 - i}{i}$.Dividing both sides by $(2 - i)$,we get $\alpha = \frac{1}{i}$.Since $\frac{1}{i} = -i$,the other root is $\alpha = -i$.

If one root of the quadratic equation $ix^2 - 2(i + 1)x + (2 - i) = 0$ is $2 - i$,then the other root is

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