If the sum of the zeros is 2 and the product | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The general form of a quadratic polynomial is given by $p(x) = k[x^{2} - (	ext{sum of zeros})x + (	ext{product of zeros})],$ where $k$ is a non-

Vedclass · Accepted Answer

$p(x)=4(x^{2}-2x+3)$

Vedclass · Answer

(D) The general form of a quadratic polynomial is given by $p(x) = k[x^{2} - (	ext{sum of zeros})x + (	ext{product of zeros})],$ where $k$ is a non-zero constant.Given that the sum of the zeros is $2$ and the product of the zeros is $3.$Substituting these values into the formula,we get $p(x) = k[x^{2} - 2x + 3].$Comparing this with the given options,if we take $k = 4,$ the polynomial becomes $p(x) = 4(x^{2} - 2x + 3).$Therefore,the correct option is $D.$

If the sum of the zeros is $2$ and the product of the zeros is $3,$ then the quadratic polynomial is........

Similar Questions

For the given sum and product of zeroes,find a quadratic polynomial. Also,find the zeroes of this polynomial by factorisation:
Sum of zeroes = $\frac{-3}{2 \sqrt{5}}$,Product of zeroes = $-\frac{1}{2}$

The product of two polynomials is $x^{2}-x-72$ and if one of the polynomials is $(x+8)$,then the other polynomial is $\ldots \ldots \ldots \ldots . .$

The zeroes of the quadratic polynomial $x^{2}+99x+127$ are

From the following figure,find the number of zeros of $y=p(x)$ :

The graph of $\ldots \ldots \ldots$ is a curve open upwards.

Vedclass Test Series

Exam Paper Generator

Online Exam Module