If the operatorname{Arg} z_1 and operatorname | vedclass

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(C) Given that $\operatorname{Arg} z_1 = \frac{\pi}{3}$.We know that $\operatorname{Arg} \overline{z_2} = -\operatorname{Arg} z_2$.Given $\operatornam

Vedclass · Accepted Answer

$\frac{2 \pi}{15}$

Vedclass · Answer

(C) Given that $\operatorname{Arg} z_1 = \frac{\pi}{3}$.We know that $\operatorname{Arg} \overline{z_2} = -\operatorname{Arg} z_2$.Given $\operatorname{Arg} \overline{z_2} = \frac{\pi}{5}$,therefore $\operatorname{Arg} z_2 = -\frac{\pi}{5}$.Now,$\operatorname{Arg} z_1 + \operatorname{Arg} z_2 = \frac{\pi}{3} - \frac{\pi}{5}$.Taking the least common multiple,we get $\frac{5\pi - 3\pi}{15} = \frac{2\pi}{15}$.

If the $\operatorname{Arg} z_1$ and $\operatorname{Arg} \overline{z_2}$ are $\frac{\pi}{3}$ and $\frac{\pi}{5}$ respectively,then the value of $\operatorname{Arg} z_1 + \operatorname{Arg} z_2$ is

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