If the absolute error is $0.05 \ m$ for a measured length of $5 \ m$, what is the percentage error (in $\%$)?

In the measurement of a physical quantity $X = \frac{A^2 B}{C^{1/3} D^3}$, the percentage errors introduced in the measurements of the quantities $A, B, C$, and $D$ are $2 \%, 2 \%, 4 \%$, and $5 \%$, respectively. Then, the minimum amount of percentage error in the measurement of $X$ is contributed by:

The error in the measurement of force acting normally on a square plate is $3 \%$. If the error in the measurement of the side of the plate is $1 \%$, then the error in the determination of the pressure acting on the plate is (in $\%$)

The current in a diode is given by the equation $I = (e^{1000V/T} - 1)$,where $V$ is the applied voltage in volts and $T$ is the absolute temperature in kelvin. $A$ student measures the current as $11 \text{ mA}$ at $300 \text{ K}$. If the error in measuring voltage is $\pm 0.01 \text{ V}$,the error in the value of current in $\text{mA}$ is:

The maximum error in the measurement of mass and length is $4 \%$ and $3 \%$ respectively. The error in the measurement of density of a cube will be (in $\%$)

If $P = \frac{A^3}{B^{5/2}}$ and $\Delta A$ is the absolute error in $A$ and $\Delta B$ is the absolute error in $B$,then the absolute error $\Delta P$ in $P$ is: