If the average terminal velocity of a rain dr | vedclass

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(C) Given that,Terminal velocity of rain, $v = 2 \,m/s$Depth of rain, $h = 100 \,cm = 1 \,m$Surface area, $A = 1 \,m^2$Volume of water, $V = A 	imes

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$2 	imes 10^3 \,J$

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(C) Given that,Terminal velocity of rain, $v = 2 \,m/s$Depth of rain, $h = 100 \,cm = 1 \,m$Surface area, $A = 1 \,m^2$Volume of water, $V = A 	imes h = 1 \,m^2 	imes 1 \,m = 1 \,m^3$Density of water, $ho = 10^3 \,kg/m^3$Mass of water, $m = V 	imes ho = 1 \,m^3 	imes 10^3 \,kg/m^3 = 10^3 \,kg$The energy transferred by the rain to the surface is equal to the kinetic energy of the rain falling on that area.Kinetic Energy, $K = \frac{1}{2} m v^2$$K = \frac{1}{2} 	imes 10^3 \,kg 	imes (2 \,m/s)^2$$K = \frac{1}{2} 	imes 10^3 	imes 4 = 2 	imes 10^3 \,J$Therefore, the energy transferred per square metre is $2 	imes 10^3 \,J$.

If the average terminal velocity of a rain drop is $2 \,m/s$, then the energy transferred by rain to each square metre of the surface at a place which receives $100 \,cm$ of rain in a year is

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