If the equation 4x^2 + hxy + y^2 = 0 represen | vedclass

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(D) The general equation of a pair of lines passing through the origin is $ax^2 + 2hxy + by^2 = 0$. For the lines to be coincident,the condition is $h

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$4$ or $-4$

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(D) The general equation of a pair of lines passing through the origin is $ax^2 + 2hxy + by^2 = 0$. For the lines to be coincident,the condition is $h^2 - ab = 0$. Comparing $4x^2 + hxy + y^2 = 0$ with $ax^2 + 2h'xy + by^2 = 0$,we have $a = 4$,$2h' = h$,and $b = 1$. The condition for coincidence is $(h')^2 - ab = 0$. Substituting $h' = \frac{h}{2}$,we get $(\frac{h}{2})^2 - (4)(1) = 0$. $\frac{h^2}{4} = 4$. $h^2 = 16$. $h = \pm 4$. Since the options provided are limited,the correct value is $4$ or $-4$.

If the equation $4x^2 + hxy + y^2 = 0$ represents coincident lines,then $h$ is equal to

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