If the line $\frac{x - 1}{2} = \frac{y + 1}{3} = \frac{z - 2}{4}$ meets the plane $x + 2y + 3z = 15$ at a point $P$,then the distance of $P$ from the origin is

  • A
    $\frac{\sqrt{5}}{2}$
  • B
    $2\sqrt{5}$
  • C
    $\frac{9}{2}$
  • D
    $\frac{7}{2}$

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