If the mean and the variance of a binomial variate $X$ are $2$ and $1$ respectively,then the probability that $X$ takes a value greater than or equal to one is

  • A
    $\frac{9}{16}$
  • B
    $\frac{3}{4}$
  • C
    $\frac{1}{16}$
  • D
    $\frac{15}{16}$

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