If the molar conductivities (in $S \ cm^2 \ mol^{-1}$) of $NaCl$,$KCl$,and $NaOH$ at infinite dilution are $126$,$150$,and $250$,respectively,the molar conductivity of $KOH$ (in $S \ cm^2 \ mol^{-1}$) is

  • A
    $526$
  • B
    $226$
  • C
    $26$
  • D
    $274$

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Similar Questions

Given below is the plot of the molar conductivity vs $\sqrt{concentration}$ for $KCl$ in aqueous solution. If,for the higher concentration of $KCl$ solution,the resistance of the conductivity cell is $100 \ \Omega$,then the resistance of the same cell with the dilute solution is '$x$' $\Omega$. The value of $x$ is $............$ ($Nearest$ $integer$)

Which of the following statements regarding the solution of an electrolyte is not correct?

How does the conductivity of a strong electrolyte change upon dilution?

What is the conductivity of $0.02 \ M \ KCl$ solution if the cell constant is $1.29 \ cm^{-1}$ and the resistance is $645 \ \Omega$?

Resistance of a cell containing $0.02 \ M \ KCl$ solution is $164 \ \Omega$. If the cell is filled with $0.05 \ M \ AgNO_3$,the resistance becomes $75.8 \ \Omega$. Calculate the following: [Conductivity of $0.02 \ M \ KCl = 2.768 \times 10^{-3} \ \Omega^{-1} \ cm^{-1}$] $(i)$ Conductivity of $0.05 \ M \ AgNO_3$ (ii) Molar conductivity of $AgNO_3$ solution.

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