If the probability distribution of a random variable $X$ is given by the following table, then the mean of $X$ is:
$X = x$$0$$2$$4$$6$$8$$10$
$P(X = x)$$0$$k$$2k$$5k^2$$2k^2$$3k$

  • A
    $\frac{384}{121}$
  • B
    $\frac{60}{13}$
  • C
    $\frac{163}{25}$
  • D
    $\frac{326}{49}$

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