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(C) Let the sides of a $	riangle ABC$ be $a, b,$ and $c$. Since $\frac{1}{a}, \frac{1}{b}, \frac{1}{c}$ are in $H$.$P$.,it implies that $a, b, c$ are

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Harmonic progression

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(C) Let the sides of a $	riangle ABC$ be $a, b,$ and $c$. Since $\frac{1}{a}, \frac{1}{b}, \frac{1}{c}$ are in $H$.$P$.,it implies that $a, b, c$ are in $A$.$P$. We know that the ex-radii are given by $r_1 = \frac{\Delta}{s-a}, r_2 = \frac{\Delta}{s-b}, r_3 = \frac{\Delta}{s-c}$. Since $a, b, c$ are in $A$.$P$.,then $s-a, s-b, s-c$ are also in $A$.$P$. Therefore,their reciprocals $\frac{1}{s-a}, \frac{1}{s-b}, \frac{1}{s-c}$ are in $H$.$P$. Multiplying by $\Delta$,we get $\frac{\Delta}{s-a}, \frac{\Delta}{s-b}, \frac{\Delta}{s-c}$ are in $H$.$P$. Thus,$r_1, r_2, r_3$ are in $H$.$P$.

If the reciprocals of the lengths of the sides of a $\triangle ABC$ are in harmonic progression,then its ex-radii $r_1, r_2, r_3$ are in

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