(A) Given the cubic equation $4x^3 - 12x^2 + 11x + m = 0$. Let the roots be $A-d, A, A+d$. Sum of roots $= (A-d) + A + (A+d) = -(-12)/4 = 3$. $3A = 3

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(A) Given the cubic equation $4x^3 - 12x^2 + 11x + m = 0$. Let the roots be $A-d, A, A+d$. Sum of roots $= (A-d) + A + (A+d) = -(-12)/4 = 3$. $3A = 3 \Rightarrow A = 1$. Since $A=1$ is a root,it must satisfy the equation: $4(1)^3 - 12(1)^2 + 11(1) + m = 0$. $4 - 12 + 11 + m = 0$. $3 + m = 0 \Rightarrow m = -3$.

Class 11 Mathematics Sequences and Series Arithmetic progression

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If the roots of the equation $4x^3 - 12x^2 + 11x + m = 0$ are in arithmetic progression,then $m =$

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-$3$
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$1$
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$2$
D
$3$

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If the roots of the equation $4x^3 - 12x^2 + 11x + m = 0$ are in arithmetic progression,then $m =$

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In an arithmetic progression,if $T_m = n$ and $T_n = m$,then $T_p = \dots$

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