If the statement p leftrightarrow (q rightarr | vedclass

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(B) The statement $p \leftrightarrow (q \rightarrow p)$ is false. This biconditional is false if the truth values of $p$ and $(q \rightarrow p)$ are d

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$p \rightarrow (p \vee \sim q)$

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(B) The statement $p \leftrightarrow (q \rightarrow p)$ is false. This biconditional is false if the truth values of $p$ and $(q \rightarrow p)$ are different. If $p$ is $T$,then $(q \rightarrow T)$ is $T$,so $T \leftrightarrow T$ is $T$. If $p$ is $F$,then $(q \rightarrow F)$ must be $T$ for the biconditional to be false. For $(q \rightarrow F)$ to be $T$,$q$ must be $F$. Thus,$p \equiv F$ and $q \equiv F$. Now,check option $(B)$: $p$ $\rightarrow (p \vee \sim q) \equiv F$ $\rightarrow (F \vee \sim F) \equiv F$ $\rightarrow (F \vee T) \equiv F$ $\rightarrow T \equiv T$. Since the result is $T$,option $(B)$ is the correct statement pattern.

If the statement $p \leftrightarrow (q \rightarrow p)$ is false,then the true statement/statement pattern is

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