If the vertices of $\Delta ABC$ are $A=(2,3,5), B=(-1,3,2), C=(3,5,-2)$,then the area of the $\Delta ABC$ (in sq. units) is

  • A
    $6 \sqrt{2}$
  • B
    $8 \sqrt{3}$
  • C
    $9 \sqrt{2}$
  • D
    $8 \sqrt{2}$

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