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(B) According to the De Broglie relation,the wavelength $\lambda$ is given by $\lambda = \frac{h}{mv}$.Given that both particles have the same velocit

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Mass of $A$ is half that of $B$

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(B) According to the De Broglie relation,the wavelength $\lambda$ is given by $\lambda = \frac{h}{mv}$.Given that both particles have the same velocity $(v_A = v_B = v)$,the wavelength is inversely proportional to the mass: $\lambda \propto \frac{1}{m}$.We are given $\lambda_A = 2\lambda_B$.Substituting the relation: $\frac{h}{m_A v} = 2 	imes \frac{h}{m_B v}$.Simplifying this,we get $\frac{1}{m_A} = \frac{2}{m_B}$,which implies $m_B = 2m_A$ or $m_A = \frac{1}{2}m_B$.Therefore,the mass of particle $A$ is half that of particle $B$.

If two particles $A$ and $B$ are moving with the same velocity,but the wavelength of $A$ is found to be double that of $B$. Which of the following statements is correct?

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