In Delta XYZ,X-P-Y,X-Q-Z and overline{PQ} par | vedclass

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(A) Given that in $\Delta XYZ$,$\overline{PQ} \parallel \overline{YZ}$.According to the Basic Proportionality Theorem (Thales Theorem),if a line is dr

Vedclass · Accepted Answer

$1.8$

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(A) Given that in $\Delta XYZ$,$\overline{PQ} \parallel \overline{YZ}$.According to the Basic Proportionality Theorem (Thales Theorem),if a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points,then the other two sides are divided in the same ratio.Therefore,$\frac{XP}{XY} = \frac{XQ}{XZ}$.Given values are $XY = 5.6$,$XP = 1.4$,and $XZ = 7.2$.Substituting these values into the equation:$\frac{1.4}{5.6} = \frac{XQ}{7.2}$.Simplifying the fraction $\frac{1.4}{5.6} = \frac{1}{4}$.So,$\frac{1}{4} = \frac{XQ}{7.2}$.$XQ = \frac{7.2}{4} = 1.8$.Thus,the value of $XQ$ is $1.8$.

In $\Delta XYZ$,$X-P-Y$,$X-Q-Z$ and $\overline{PQ} \parallel \overline{YZ}$. If $XY = 5.6$,$XP = 1.4$ and $XZ = 7.2$,find $XQ$.

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