In $\Delta ABC$,$m \angle A = 90^{\circ}$ and $\overline{AD}$ is an altitude. If $AB = \sqrt{5}$ and $BD = 2$,then the length of hypotenuse $\overline{BC}$ is.........
- A$2\sqrt{5}$
- B$3$
- C$\sqrt{10}$
- D$2.5$
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