(B) To find the empirical formula,divide the mass ratio by the atomic mass of each element:$H: 1 / 1 = 1$$C: 3 / 12 = 0.25$$O: 4 / 16 = 0.25$$N: 7 / 1

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(B) To find the empirical formula,divide the mass ratio by the atomic mass of each element:$H: 1 / 1 = 1$$C: 3 / 12 = 0.25$$O: 4 / 16 = 0.25$$N: 7 / 14 = 0.5$Now,divide each value by the smallest value $(0.25)$:$H: 1 / 0.25 = 4$$C: 0.25 / 0.25 = 1$$O: 0.25 / 0.25 = 1$$N: 0.5 / 0.25 = 2$The ratio of atoms is $H:C:O:N = 4:1:1:2$.Therefore,the empirical formula is $H_4CON_2$.

Class 11 Chemistry Some Basic Concepts of Chemistry Percentage composition and Molecular formula

Medium

In a compound,the ratio of masses of $H, C, O,$ and $N$ is $1:3:4:7$. The empirical formula is

A
$HC_3O_4N_7$
B
$H_4CON_2$
C
$HC_4O_2N_2$
D
None of these

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Percentage composition and Molecular formula

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In a compound,the ratio of masses of $H, C, O,$ and $N$ is $1:3:4:7$. The empirical formula is

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