In a diode AM-detector,the output circuit con | vedclass

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(B) For proper demodulation in a diode $AM$-detector,the condition $\frac{1}{f_c} \ll RC$ must be satisfied,where $f_c$ is the carrier frequency.Given

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No

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(B) For proper demodulation in a diode $AM$-detector,the condition $\frac{1}{f_c} \ll RC$ must be satisfied,where $f_c$ is the carrier frequency.Given:$f_c = 100 \, kHz = 10^5 \, Hz$$R = 1 \, k\Omega = 10^3 \, \Omega$$C = 10 \, pF = 10 	imes 10^{-12} \, F = 10^{-11} \, F$Calculating $\frac{1}{f_c}$:$\frac{1}{f_c} = \frac{1}{10^5} = 10^{-5} \, s$Calculating $RC$:$RC = 10^3 	imes 10^{-11} = 10^{-8} \, s$Comparing the values:We observe that $10^{-5} \, s > 10^{-8} \, s$,which means $\frac{1}{f_c} > RC$.Since the condition $\frac{1}{f_c} \ll RC$ is not satisfied,the circuit is not good for detection.

In a diode $AM$-detector,the output circuit consists of $R = 1 \, k\Omega$ and $C = 10 \, pF$. $A$ carrier signal of $100 \, kHz$ is to be detected. Is it good?

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