In a group of 6 boys and 4 girls,four childre | vedclass

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(D) Total number of children $= 6 + 4 = 10$.Total number of ways to select $4$ children from $10$ is given by ${}^{10}C_{4} = \frac{10 	imes 9 	imes

Vedclass · Accepted Answer

$209$

Vedclass · Answer

(D) Total number of children $= 6 + 4 = 10$.Total number of ways to select $4$ children from $10$ is given by ${}^{10}C_{4} = \frac{10 	imes 9 	imes 8 	imes 7}{4 	imes 3 	imes 2 	imes 1} = 210$.Number of ways to select $0$ boys (i.e.,all $4$ are girls) is given by ${}^{4}C_{4} = 1$.To find the number of ways to select at least one boy,we subtract the number of ways to select no boys from the total number of ways.Number of ways $= {}^{10}C_{4} - {}^{4}C_{4} = 210 - 1 = 209$.

In a group of $6$ boys and $4$ girls,four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?

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