In a packet containing 400 screws,120 screws | vedclass

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(C) Total number of screws in the packet $= n = 400$.Number of defective screws $= 120$.Number of non-defective screws $= 400 - 120 = 280$.Let $E$ be

Vedclass · Accepted Answer

$0.7$

Vedclass · Answer

(C) Total number of screws in the packet $= n = 400$.Number of defective screws $= 120$.Number of non-defective screws $= 400 - 120 = 280$.Let $E$ be the event of picking up a non-defective screw.The number of outcomes favourable to event $E$ is $m = 280$.The probability of picking up a non-defective screw is given by $P(E) = \frac{m}{n} = \frac{280}{400}$.Simplifying the fraction,$P(E) = \frac{28}{40} = \frac{7}{10} = 0.7$.

In a packet containing $400$ screws,$120$ screws are defective. $A$ screw is picked up randomly from the packet. Then,the probability that the screw picked up is non-defective is .........

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