In a photoelectric emission experiment,the stopping potential for a given metal is $V$ volt,when radiation of wavelength $\lambda$ is used. If radiation of wavelength $2 \lambda$ is used with the same metal,then the stopping potential (in volt) will be. [Given: $c = \text{velocity of light}$,$e = \text{charge on electron}$,$h = \text{Planck's constant}$]

  • A
    $V - \frac{hc}{2e\lambda}$
  • B
    $V + \frac{hc}{2e\lambda}$
  • C
    $\frac{V}{2}$
  • D
    $2V$

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